30b^2+b=2

Solution for 30b^2+b=2 equation:

30b^2+b=2

We move all terms to the left:

30b^2+b-(2)=0

a = 30; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·30·(-2)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{241}}{2*30}=\frac{-1-\sqrt{241}}{60}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{241}}{2*30}=\frac{-1+\sqrt{241}}{60}
$